Hi, I cannot get this question: f(x) = sqrt(3x)/(x^2-4), find f'(x) at x=3. I tried using the quotient rule but it doesn't work.
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Originally Posted by millerst Hi, I cannot get this question: f(x) = sqrt(3x)/(x^2-4), find f'(x) at x=3. I tried using the quotient rule but it doesn't work. $\displaystyle f'(x) = \frac{(x^2-4) \cdot \frac{3}{2\sqrt{3x}} - \sqrt{3x} \cdot 2x}{(x^2-4)^2} $ evaluate $\displaystyle f'(3)$
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