so the function is y= ln(arcsec(3x+1))
i know that the derivative of lnx is 1/x
so, based on this fact, and the chain rule, i said:
y'= 1/arcsec(3x+1) * 1/x sqrt(x^2-1) * 3
i know that's not the neatest way to write it.. can someone tell me if this is correct?