so the function is y= ln(arcsec(3x+1))

i know that the derivative of lnx is 1/x

so, based on this fact, and the chain rule, i said:

y'= 1/arcsec(3x+1) * 1/x sqrt(x^2-1) * 3

i know that's not the neatest way to write it.. can someone tell me if this is correct?