h(x) = −12 ln( tanx + secx ) + ln( 6 tanx ) − 8 ln( secx)
find h'(x)
alright so this is the third time doing this question, obviously i'm missing something here. i seperated each section
a) −12 ln( tanx + secx )
b) ln( 6 tanx )
c) − 8 ln( secx)
to do the chain rule on each and then combined them again into my final equation, which is wrong.
i don't know how to format text on here so try to bear with the brackets (sorry)
here's my equation:
([-12*
[([sec(x)]^2)+sec(x)*tan(x)
]]/[tan(x)+sec(x)])+([6*([sec(x)]^2)]/[6*tan(x)])-([8*sec(x)*tan(x)]/[sec(x)])
help please
thanks,
brittany