h(x) = −12 ln( tanx + secx ) + ln( 6 tanx ) − 8 ln( secx)

find h'(x)

alright so this is the third time doing this question, obviously i'm missing something here. i seperated each section

a) −12 ln( tanx + secx )

b) ln( 6 tanx )

c) − 8 ln( secx)

to do the chain rule on each and then combined them again into my final equation, which is wrong.

i don't know how to format text on here so try to bear with the brackets (sorry)

here's my equation:

([-12*

[([sec(x)]^2)+sec(x)*tan(x)

]]/[tan(x)+sec(x)])+([6*([sec(x)]^2)]/[6*tan(x)])-([8*sec(x)*tan(x)]/[sec(x)])

help please

thanks,

brittany