Results 1 to 5 of 5

Math Help - Derivative Help

  1. #1
    Junior Member Morphayne's Avatar
    Joined
    May 2008
    Posts
    31

    Unhappy Derivative Help

    Can somebody please give me the derivative of the following:

    A(x) = x^2 + \sqrt3(\frac{16-2x}{3})^2

    \frac{16-2x}{3} is supposed to be inside brackets all squared. I don't know how to fix the brackets. Sorry.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Member
    Joined
    Dec 2008
    Posts
    130
    Quote Originally Posted by Morphayne View Post
    Can somebody please give me the derivative of the following:

    A(x) = x^2 + \sqrt3(\frac{16-2x}{3})^2

    \frac{16-2x}{3} is supposed to be inside brackets all squared. I don't know how to fix the brackets. Sorry.
    A(x) = x^2 + \sqrt3(\frac{16-2x}{3})^2

    so

    2x + 2\sqrt{3}(\frac{16-2x}{3})(\frac{-2}{3})
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Senior Member mollymcf2009's Avatar
    Joined
    Jan 2009
    From
    Charleston, SC
    Posts
    490
    Awards
    1
    Quote Originally Posted by Morphayne View Post
    Can somebody please give me the derivative of the following:

    A(x) = x^2 + \sqrt3(\frac{16-2x}{3})^2

    \frac{16-2x}{3} is supposed to be inside brackets all squared. I don't know how to fix the brackets. Sorry.

    First, rewrite it like this:

    A(x) = x^2 + \frac{\sqrt{3}}{9} (16 - 2x)^2

    Then try it. Don't forget the chain rule for the (16 - 2x)^2
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Junior Member Morphayne's Avatar
    Joined
    May 2008
    Posts
    31
    What do you guys get when you solve A'(x)=0?
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Senior Member mollymcf2009's Avatar
    Joined
    Jan 2009
    From
    Charleston, SC
    Posts
    490
    Awards
    1
    Quote Originally Posted by Morphayne View Post
    What do you guys get when you solve A'(x)=0?

    I get:

    x = \frac{64}{6\sqrt{3} + 8}
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. contuous weak derivative $\Rightarrow$ classic derivative ?
    Posted in the Differential Geometry Forum
    Replies: 2
    Last Post: April 22nd 2011, 02:37 AM
  2. Replies: 0
    Last Post: January 24th 2011, 11:40 AM
  3. [SOLVED] Definition of Derivative/Alt. form of the derivative
    Posted in the Calculus Forum
    Replies: 2
    Last Post: September 23rd 2010, 06:33 AM
  4. Derivative Increasing ==> Derivative Continuous
    Posted in the Differential Geometry Forum
    Replies: 2
    Last Post: February 23rd 2010, 10:58 AM
  5. Replies: 2
    Last Post: November 6th 2009, 02:51 PM

Search Tags


/mathhelpforum @mathhelpforum