Can somebody please give me the derivative of the following:
$\displaystyle A(x) = x^2 + \sqrt3(\frac{16-2x}{3})^2$
$\displaystyle \frac{16-2x}{3}$ is supposed to be inside brackets all squared. I don't know how to fix the brackets. Sorry.
Can somebody please give me the derivative of the following:
$\displaystyle A(x) = x^2 + \sqrt3(\frac{16-2x}{3})^2$
$\displaystyle \frac{16-2x}{3}$ is supposed to be inside brackets all squared. I don't know how to fix the brackets. Sorry.