Say I have a sphere and it has a radius of 3. How could I find it's volume using the disk method and integration?

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- Mar 9th 2009, 04:43 PMgammamanvolume of sphere using disk method.
Say I have a sphere and it has a radius of 3. How could I find it's volume using the disk method and integration?

- Mar 9th 2009, 06:40 PMMentia
By disk method I assume you mean using cylindrical coordinates. In this case you need to think about your limits on z. At what z is the top and bottom of the circle? At .

So what is the equation of our circle? Its:

We know from polar coordinates that . Then the equation of our circle is now:

or

But in polar coordinates, a negative r doesn't make sense so we will say:

.

So now what is the area of any disk in our circle? It is:

But we want to add up all our disks, so we multiply them by a little bit of height, dz, and then integrate over z also:

Does it work? Lets evaluate it, we know we should get

Indeed, if you went through and solved the triple integral you would get . - Mar 9th 2009, 06:45 PMmollymcf2009
Start by drawing the top half of a circle. Since I assume you were not given a specific location of the sphere on the graph, I would just center it at the origin. The top half of (since radius is 3) will go from (-3,0) to (3,0). Your disk will rotate about the x axis.

Since you are only using 1/2 of a circle, use the equation:

Volume

Can you take it from here?