integrate ((x^2+4)^1/2)/x dx ; u^2=x^2+4 x=(u^2-4)^1/2 dx=u/(u^2-4)^1/2 du =integral u/(u^2-4)^1/2 x u/(u^2-4)^1/2 du =integral u^2/u^2 -4 du not sure if the above is correct/if it is, how to integrate it?
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Originally Posted by Erghhh integrate ((x^2+4)^1/2)/x dx ; u^2=x^2+4 x=(u^2-4)^1/2 dx=u/(u^2-4)^1/2 du =integral u/(u^2-4)^1/2 x u/(u^2-4)^1/2 du =integral u^2/u^2 -4 du not sure if the above is correct/if it is, how to integrate it? $\displaystyle \int (u^2/u^2 -4) du$ $\displaystyle = \int (1 -4)du$ $\displaystyle =\int -3du$ $\displaystyle =-3u+c$ did you mean: $\displaystyle \int (u^2/(u^2 -4)) du$ ? if so, use parentheses.
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