Thread: Simple antiderivative question...

How do you take the antiderivative of something to the -1 power? Specifically I'm working with (12-10x)^-1. Using normal antideriv rules it would just be (12-10x)^0/0, which is irrational, could someone answer this for me? Thanks

Originally Posted by fattydq

How do you take the antiderivative of something to the -1 power? Specifically I'm working with (12-10x)^-1. Using normal antideriv rules it would just be (12-10x)^0/0, which is irrational, could someone answer this for me? Thanks

antiderivative involves the ln function.



normally, one learns how to find the derivative of ln functions before tackling antiderivatives.

Originally Posted by skeeter

antiderivative involves the ln function.



normally, one learns how to find the derivative of ln functions before tackling antiderivatives.

Yeah well my calc I class was a joke, I passed out with an A and now I'm struggling hard with calc II. thanks for the reply though

Originally Posted by skeeter

antiderivative involves the ln function.



normally, one learns how to find the derivative of ln functions before tackling antiderivatives.

Where did the -1/10 come from in your solution?

Originally Posted by fattydq

Yeah well my calc I class was a joke, I passed out with an A and now I'm struggling hard with calc II. thanks for the reply though



Where did the -1/10 come from in your solution?

He made the substitution u= 12- 10x so du= -10 dx so dx= -(1/10)du.