roll theorem prove question..
suppose that to the quadratic equation x^2+px+q=0
has two roots
prove that for
there are n different roots on the interval (x1,x2)
by rolls theorem we have a point "c" on the interval of (x1,x2) for which
then they say
"that we can get another solution "g" on the interval of (x1,c) using rolls theorem"
but its not rolls theorem
we dont have two points for which there is a point "j" for which f'(j)=0
we have f(x1)=0 and f'(c)=0 (but its not f(c)=0 )