Follow Math Help Forum on Facebook and Google+
Originally Posted by colaname Here is your region:
Can you try to set up the integral?
from the graph you'll find that the equations intersect at (0,0) and (1,1)
Also the seocond equation is on top of the first.
Thus we have the integral
∫(2x-x²) - (x²) from 0 to 1
∫2x-x² - ∫x² both from 0 to 1
Can you take it from there?
View Tag Cloud