∫sin³(x/2) from 0 to pi/3.
I have..
∫sin²(x/2)sin(x/2)
∫[1-cos²(x/2)]sin(x/2)
∫sin(x/2) - cos²(x/2)sin(x/2)
∫sin(x/2) - ∫cos²(x/2)sin(x/2)
I don't know where to go from there... Please help me.
In the first integral, make the substitution . The new lower limit is and the new upper limit is
So the integral
For the second integral, make the substitution . The new lower limit is and the new upper limit is
So the integral
Can you take it from here and solve each integral?