now integrate the series on the RHS term for term ...
the integral is
3[int.] e^x - 1 / 8x
Im not sure what exactly its asking me... infinite integral using infinite series??
i know that e^x = [Sum.]n=0 to infinite x^n / n!
but i dont know what comes next or even if i have to use that??
An explanation about how to go about solving this would be great