Don't forget to go all the way down to "x". When you differentiate "cos(3x)", you differentiate the cosine, and then the 3x!
. . . . .
Differentiate the function. You do not need to simplify your answer
f(x)=sin(cos3x)+cos(5sinx)
i thought in order to go about doing this you had to usethe chain rule for
each component
d/dx(sin(cos3x))+d/dx(cos(5sinx))
d/dx(sin(cos3x))
using chain rule = cos(cos3x)* -sin3x
d/dx(cos(5sinx))
using chain rule = -sin(5sinx)* 5cosx
so f '(x) = [cos(cos3x)* -sin3x] + [-sin(5sinx)* 5cosx]
all this is a new concept just recently learned in my math class, and i really don't know what i'm doing. hopefully i'm somewhat on the right track??
thanks in advance!