okay, so the problem is: integral from 2 to 6 y/(y-2)^1/2 dy i know you have to start by saying lim a-->2+ integral from a to 6 y/(y-2)^1/2 but then i'm kind of blanking on how to integrate/go from there
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let integrate, back substitute, then evaluate your improper integral
should i be getting a negative answer for this..? i got -8/3
it is possible, you can get a negative answer and since it is a proper integral, you can check the answer even with a ti-83 plus.
would you mind telling me how to do that? :x edit: i got it, nevermind, thank you very much!
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