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Thread: integration

  1. #1
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    integration

    given that $\displaystyle y^{\frac{1}{2}} = x^{\frac{1}{3}} +3 $

    a) show that $\displaystyle y = x^{\frac{2}{3}} + Ax^{\frac{1}{3}} + B $ where A and B are constants to be found .

    b) hence find $\displaystyle \int ydx $
    Last edited by Tweety; Mar 8th 2009 at 10:43 AM.
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  2. #2
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    [quote=Tweety;278593]given that $\displaystyle y^{\frac{1}{2}} = x^{\frac{1}{3}} +3 $

    a) show that $\displaystyle y = x^{\frac{2}{3}} + Ax^{\frac{1}{3}} + B $ where A and B are constants to be found .

    b) hence find $\displaystyle \intydx $
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  3. #3
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    I can't seem to edit my post, anyone know why ?
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  4. #4
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    Quote Originally Posted by Tweety View Post
    given that $\displaystyle y^{\frac{1}{2}} = x^{\frac{1}{3}} +3 $

    a) show that $\displaystyle y = x^{\frac{2}{3}} + Ax^{\frac{1}{3}} + B $ where A and B are constants to be found .

    b) hence find $\displaystyle \int y \, dx $
    $\displaystyle y = (x^{\frac{1}{3}} +3)^2$

    $\displaystyle y = x^{\frac{2}{3}} + 6x^{\frac{1}{3}} + 9$

    now find ...

    $\displaystyle \int x^{\frac{2}{3}} + 6x^{\frac{1}{3}} + 9 \, dx$

    editing posts after 15 minutes has been disabled ... use the "preview" feature.
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  5. #5
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    if you can't edit it, then just re-post your question (probably in this thread)
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