integration

**Tweety** · March 8th, 2009, 09:19 AM

given that $y^{\frac{1}{2}} = x^{\frac{1}{3}} +3$

a) show that $y = x^{\frac{2}{3}} + Ax^{\frac{1}{3}} + B$ where A and B are constants to be found .

b) hence find $\int ydx$

**Peritus** · March 8th, 2009, 09:21 AM

[quote=Tweety;278593]given that $y^{\frac{1}{2}} = x^{\frac{1}{3}} +3$

a) show that $y = x^{\frac{2}{3}} + Ax^{\frac{1}{3}} + B$ where A and B are constants to be found .

b) hence find $\intydx$

**Tweety** · March 8th, 2009, 09:22 AM

I can't seem to edit my post, anyone know why ?

**skeeter** · March 8th, 2009, 09:42 AM

Originally Posted by Tweety

given that $y^{\frac{1}{2}} = x^{\frac{1}{3}} +3$

a) show that $y = x^{\frac{2}{3}} + Ax^{\frac{1}{3}} + B$ where A and B are constants to be found .

b) hence find $\int y \, dx$

$y = (x^{\frac{1}{3}} +3)^2$

$y = x^{\frac{2}{3}} + 6x^{\frac{1}{3}} + 9$

now find ...

$\int x^{\frac{2}{3}} + 6x^{\frac{1}{3}} + 9 \, dx$

editing posts after 15 minutes has been disabled ... use the "preview" feature.

**tbm206** · March 8th, 2009, 09:45 AM

if you can't edit it, then just re-post your question (probably in this thread)

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