# Math Help - convergent and divergent improper integrals

1. ## convergent and divergent improper integrals

Did I do this one right? :

$\int \frac{4}{\sqrt{6-x}}dx$ [0,6]

$= lim \int \frac{4}{\sqrt{6-x}}dx$ [0,6]
$x->6^-$

$= lim (\frac{4}{(6-x)^2})| [0,b]$
$x->6^-$

$= infinity - \frac{1}{9} = diverges?$

2. Originally Posted by saiyanmx89
Did I do this one right? :

$\int \frac{4}{\sqrt{6-x}}dx$ [0,6]

$= lim \int \frac{4}{\sqrt{6-x}}dx$ [0,6]
$x->6^-$

$= lim (\frac{4}{(6-x)^2})| [0,b]$
$x->6^-$

$= infinity - \frac{1}{9} = diverges?$
$\int \frac{4}{\sqrt{6-x}} \, dx = -8\sqrt{6-x} + C$