If we are told that , where .
Prove that the polynomial has at least one real zero.
Well this partiular statement is independent of as I said any odd order
polynomial, but in this case yes I suppose could in principle
be zero.
In fact I do have another method using Descartes rule of signs which
does use the condition, which I beleive handles the possibility that
(but I don't intend to check that now).
RonL