at t time a particle is moving along the x axis at position x. the relationship between x and t is given by tx=x^2 +8. at x = 2 the velocity of the particle is:

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- Mar 7th 2009, 08:21 AMLexiRaetime, velocity, position of a particle
at t time a particle is moving along the x axis at position x. the relationship between x and t is given by tx=x^2 +8. at x = 2 the velocity of the particle is:

- Mar 7th 2009, 08:38 AMMentia
Did you mean to write t(x) = x^2 + 8 instead of tx = x^2 + 8? I hope so because that makes it easier.

Then:

$\displaystyle t=x^{2}+8$

then

$\displaystyle x=\pm \sqrt[ ]{ t-8} $

then

$\displaystyle velocity=\frac{dx }{dt }=\pm \frac{1}{2}\frac{1}{\sqrt[]{t-8}} = \frac{1}{2x}$

Then if x = 2, velocity = 1/4

Seem reasonable? - Mar 7th 2009, 09:09 AMHallsofIvy