[-infinity,0]

I set this equal to the limit as x goes to -infinity and subbed in a for -infinity. Then I solved the definite improper integral getting= . I got (1/2)-0 = 1/2. Did I do this right??

Printable View

- Mar 7th 2009, 05:48 AMsaiyanmx89improper integrals
[-infinity,0]

I set this equal to the limit as x goes to -infinity and subbed in a for -infinity. Then I solved the definite improper integral getting= . I got (1/2)-0 = 1/2. Did I do this right?? - Mar 7th 2009, 06:06 AMMush
- Mar 7th 2009, 06:06 AMskeeter