Find the general solution of the second-order, linear, inhomogeneous differential equation: y′′ + 3y′ + 2y = Please help solve this equation so far I have done: z^2 +3z+2=0 (z+2)(z+1)=0 z=-2,-1
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Originally Posted by ronaldo_07 Find the general solution of the second-order, linear, inhomogeneous differential equation: y′′ + 3y′ + 2y = Please help solve this equation so far I have done: z^2 +3z+2=0 (z+2)(z+1)=0 z=-2,-1 Looks good up to here. The homogeneous solution is Here, I would consider using Variation of Parameters. Let . Thus, we need to evaluate three different Wronskians. Thus, and Thus, and Thus, our solution is Does this make sense?
Could you explain Thus, we need to evaluate three different Wronskians the W W1 W2. How this is calculated please. Thanks.
Originally Posted by ronaldo_07 Could you explain Thus, we need to evaluate three different Wronskians the W W1 W2. How this is calculated please. Thanks. See my explanation here.
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