[SOLVED] Another work as a Riemann sum problem

**fattydq** · March 6th 2009, 10:29 AM

I've attached it. Again in this problem we aren't given a spring constant or a force so I have no idea how I'd set up the problem to find WORK when I don't have the variables needed to find work. I thought maybe it'd be the (incorrect) answer I chose because 3 would just be the force, but obviously as I already partially knew this isn't the case.

Could someone point me in the right direction?

**galactus** · March 6th 2009, 11:18 AM

The work required to lift the chain is:

$3\int_{0}^{500}(500-y)dy$

The work needed to lift the 500 lbs of coal is $500(500)=250,000$

The work needed to lift the chain and the coal is then:

$250,000+3\int_{0}^{500}(500-y)dy$

This is in foot-pounds

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