$\displaystyle \int \frac{x}{\sqrt{3-x^4}}dx$
$\displaystyle \int \frac{x}{\sqrt{\sqrt{3}^2-(x^2)^2}}dx$
$\displaystyle x = \sqrt{3}sinx$
$\displaystyle dx = \sqrt{3}cosx$
$\displaystyle \sqrt{3-(3sin^2\theta)^2}$
$\displaystyle \sqrt{3-(1 - 3sin^4\theta)}$
This is where i get stuck.
Any help is appreciated