Hi Kitizhi,
Your limits of integration look a bit off.
to find the area between first find the intersection of the two graphs by setting the two equations equal to each other
and
set up your integrals as
Hope this helps
Ok I am pretty sure what I have done is correct various things are telling me wrong so can someone tell me where I went wrong and the correct way to do it. Thanks.
dA = (top-bottom) dx
= (x^3-12x^2+20x)-(-x^3+12x^2-20x) dx
= (2x^3-24x^2+40x) dx
therefore..
∫ (2x^3-24x^2+40x) dx from x=0 to x=2
{(1/2)x^4-8x^3+20x^2} from x=0 to x=2
therefore..
((1/2)(2)^4-8(2)^3+20(2)^2) - 0
= 24
this seems to be incorrect so can someone explain to me why and how to correctly do it? Thanks
Hi Kitizhi,
Your limits of integration look a bit off.
to find the area between first find the intersection of the two graphs by setting the two equations equal to each other
and
set up your integrals as
Hope this helps
Ahh I think I get what you mean but you mis-typed the equation so the x values I got are really different..
(x^3-12x^2+20x)=(-x^3+12x^2-20x)
2x^3-24x^2+40x=0
2x(x-10)(x-2)=0
therefore x=0,2,10
so my limits should be..
I believe...correct me if I am wrong.
which should be