# Thread: patrial fraction decomp integration

1. ## patrial fraction decomp integration

can anyone help me do this integration
(dx)/(x^3 - 2x^2 + 4x - 8)

I factored the bottom to (x^2 + 4)(x - 2)

and found
A = -1/8
B = 1/4
C = 1/8

don't really know what to do next

2. Assuming those numbers are correct, the next thing to do is to separate the original fraction into two separate ones, both which can be integrated separately.

3. hmm

the integral of

(1/4) / (x^2 + 4)

is this (1/4)arctan(x/2) ?

4. Originally Posted by sleepiiee
hmm

the integral of

(1/4) / (x^2 + 4)

is this (1/4)arctan(x/2) ?
No.

$\frac{\frac{1}{4}}{x^2 + 4} = \frac{1}{8} \cdot \frac{2}{x^2 + 2^2} \, ....$