Hi

My problem tonight is I don't have a firm enough grasp of e

The question is to find all local extreme values and determine if any are absolute

f(x) = x^2 e^-x^2

So I think f'(x) = x^2 (-2xe^-x^2) + 2xe^x^2

= (1-x^2)(-2xe^x^2)

Now the critical point of (1-x^2) is x= 1 or x=-1 but I don't know what the critical point of the other part is

I am also not sure how to test for absoluteness and how do I know if it is a local min or max - how can I tell if the sign changes???

sorry lots of questions - but thanks for reading - hopefully you can help

thanks

a calculus beginner