fundamental theorem of calculus find an expression for g(x)= integral from 0 to x of f(x)dx similar to the one for f(x). f(x) = x+3 for x less than or equal to -1 f(x) = x^2 +1 for x > -1 g(x)= integral from 0 to x of f(x)dx
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Originally Posted by cm3pyro fundamental theorem of calculus find an expression for g(x)= integral from 0 to x of f(x)dx similar to the one for f(x). f(x) = x+3 for x less than or equal to -1 f(x) = x^2 +1 for x > -1 g(x)= integral from 0 to x of f(x)dx Looks straight forward. If , g(x)= . If x< -1 g(x)=
for the second function, x>-1 you said, x<-1 will this change my answer?
find an expression for g(x)= f(x)dx similar to the one for f(x). f(x) = x+3 for x -1 f(x) = x^2 +1 for x > -1 g(x)= f(x)dx
still need help with this problem, the above poster was incorrect. He switched up the functions and the bounds.. please help
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