Is the original expression ?
You are right you add 1, or 2/2, to the exponent and divide by the new exponent. If you do that you get
So I find that both you and your other answer are wrong.
Im having an issue with:
(u^(3/2))/2
i know that once i evaluate it i am supposed to add +1 to r (which is 3/2 in this case) and that would give me u^(5/2) but I thought i was also supposed to multiply 5/2 times the denominator which would give me 10/2 or 5.......
However I am confused because the answer is supposed to be:
(1/10)(u)^5/2 and when i do it my way i get 5(u)^5/2
What am I doing wrong? Any help would be great, thanks!
Haha your right i meant from what I have up there i get (1/5)(u)^5/2 but the solutions is supposed to be (1/10)(u)^5/2, so im guessing i messed up somewhere else in the problem because this is only part of it the original problem which was:
Find the following indefinite integral:
(x)(square root of 2x-1)dx
sorry i dont know how to make it look prettier
answer is supposed to be:
(1/10)(2x-1)^(5/2) + (1/6)(2x-1)^(3/2) +c