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Thread: Confused with this problem.

  1. #1
    Ral is offline
    Oct 2007

    Confused with this problem.

    Let r(t)=(t,e^-t); write the acceleration vector at time t=0 as a sum of tangential (i.e., parallel to the velocity vector) and normal (i.e., orthogonal) components.
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  2. #2
    Member Mentia's Avatar
    Dec 2008
    Bellingham, WA
    Your post is a bit confusing, but I assume you mean:

    r(t) is a parameterized curve such that x(t) = t, y(t) = e^-t.

    Then r'(t) = v(t) is parameterized by x'(t) = 1, y'(t) = -e^-t,
    and r''(t) = a(t) is parameterized by x''(t) = 0, y''(t) = e^-t.

    Then at t = 0, v(0) = (1,-1), a(0) = (0,1). However, if you want a(0) in terms of the velocity vector (1,-1) and an orthogonal vector (1,1), you can do this by eyeball and say a(0) = -(1/2)*(-1,1) + (1/2)*(1,1).
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