Find the volume of the solid that results when the region enclosed by y= the square root of x, y=0, and x=9 is revolved about the line x=9.
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Originally Posted by kinana18 Find the volume of the solid that results when the region enclosed by y= the square root of x, y=0, and x=9 is revolved about the line x=9. Use cylindrical shells in terms of x. Your integral will be: $\displaystyle \int\limits^{9}_{0} 2\pi (9-x)(\sqrt x) dx$
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