Find the surface area of the solid of revolution obtained by rotating the curve from y= 2 to y= 5 about the x-axis.
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Find the surface area of the solid of revolution obtained by rotating the curve from y= 2 to y= 5 about the x-axis.
I keep getting 580.3030543, but apparently that is not the right answer.
Since you have attempted the problem in its entirety, it's a good idea to post your work. That way it's easier for those who can help to spot your error and to see what you know/don't know.
I used the formula:
2*pi*y*sqrt(1+(dx/dy)^2)dy
From that, I got:
I know I plugged in the numbers correctly, because I checked it carefully about four times.
Bump. Anyone? I can't tell if I'm integrating properly.
