Use Implicit Differentiation:
(x^3) + (y^3) = 6xy
So I got:
(3x^2) + (3y^2)(dy/dx) = (0)(x*dy/dx) + (y)(1)
But the answer I got was wrong...any help?
In general, if c is a constant, (cf(x))'= cf'(x). If you really WANT to use the product rule, (cf(x))'= 0f(x)+ cf'(x)= cf'(x).But the answer I got was wrong...any help?
You might write, above, (6xy)'= (0)xy+ (6y)+ (6x)y'= 6xdy/dx+ 6y.