Hi there, I've been working this problem forever and I cannot come close to the right answer...

A function of the position of a car being driven on a straight road, measured in feet from some fixed point is given by:

$\displaystyle s(t)=1/3(t^2+8)^3/2$

BTW: to avoid any confusion, the $\displaystyle (t^2+8)$ is raised to $\displaystyle 3/2$

Sorry, I could not get it to look right.

I am to determine the acceleration of the car when t=1. I know I have to take the second derivative of s(t) to get the right equation to plug t into, but I can't get it for the life of me... Any suggestions?