Second derivative help!!
Hi there, I've been working this problem forever and I cannot come close to the right answer...
A function of the position of a car being driven on a straight road, measured in feet from some fixed point is given by:
BTW: to avoid any confusion, the is raised to
Sorry, I could not get it to look right.
I am to determine the acceleration of the car when t=1. I know I have to take the second derivative of s(t) to get the right equation to plug t into, but I can't get it for the life of me... Any suggestions? (Worried)
at t = 1,
=2/3 (3 + 2/3)
= 2/3 * 11/3
Above solution is assuming is in numerator of s(t)
Yes, the original s(t) is in the numerator.
However, any way I interpret your answer is incorrect...
The choices I'm given are:
arpitagarwal has answered
Originally Posted by rust1477
I missed some factors
Here i correct one
at t = 1,
=(3 + 1/3)
Hey thank you so much for showing me correct answer...
Can you elaborate a little bit on the computations you did to arrive at the second derivative?
When I computed the , I got
Is this correct for the first derivative, and if so, can you explain how you arrived at the second derivative?
Yes yu ave calculated s'(t) correct.
To calculate s''(t) use differentiation by parts.
Is that clear now?