Hello, gracy!
Make some sketches and use baby-talk . . .
The first integral says: the area under
from 0 to 1 is
square units.
The graph might look like this. Code:
|
*
| *
| *
| 7 *
|
--+-------*----
| 1
|
The second integral says: the area under
from 0 to 3 is only 
How did we lose some area?
Some of the area from 1 to 3 must be negative.
. . The graph must dip below the x-axis.
The graph might look like this. Code:
|
*
| *
| *
| 7 *
| 3
--+-------*-------+--
| 1 * -3 :
| * :
| *
And that is why: . \,dx\:=\:-3)