# Finding Values from points of inflection and avg. mean value

• Mar 1st 2009, 07:21 PM
ment2byours
Finding Values from points of inflection and avg. mean value
Let F be the function by f(x)=x^3+ax^2+bx+c and having the following properties:

(i) The graph of f has an inflection point at (0,2)
(ii) the average mean value of f(x) on the closed interval [0,-2] is -3

a.) Determine the value of a, b, and c
b.) Determine the value of x that satisfies the conclusion of the mean value theorem for f on the closed interval [0,3]

Okay so I found out that both a and b equals -1 based on the properties, but I cant fins out what c is and I'm stuck. Help please?
• May 2nd 2009, 05:36 AM
Quote:

Originally Posted by ment2byours

(i) The graph of f has an inflection point at (0,2)

that means (0,2) must lie on the curve.

hence, f(0)=2 => c=2

(Nerd)
• May 2nd 2009, 05:38 AM
ment2byours
Oh thanks, but I already solve this problem long ago. I thought I should leave it on just in case someone needs it.
• May 2nd 2009, 05:39 AM