Math Help - Vectors: Parametric Equation

1. Vectors: Parametric Equation

How would I find the direction vector in this problem?

Find parametric equations for the line that passes through the point (0, -1, 1) and the midpoint of the line segment from (2, 3, -2) to (4, -1, 5).

Please and thank you

2. Let $M_1(0,-1,1)$

The midpoint is $M_2\left(3,1,\frac{3}{2}\right)$

The parametric equations of the line $M_1M_2$ are:

$\left\{\begin{array}{lll}x=x_1+t(x_2-x_1)\\y=y_1+t(y_2-y_1)\\z=z_1+t(z_2-z_1)\end{array}\right., \ t\in\mathbf{R}$

3. So, would the midpoint be the direction vector of the line?
The answer to the question is x= 6t, y= -1 + 4t, z= 1 + t so the direction vector here is (6, 4, 1).