Results 1 to 3 of 3

Math Help - annihilators

  1. #1
    Member pberardi's Avatar
    Joined
    Dec 2008
    Posts
    85

    annihilators

    Can someone help me with this one?
    Find the operator that annihilates this function
    x^4 - x^2 + 11

    I wanna say that the solution is:
    for x^4 L1 = D^5 and for x^2 L2 = D^3
    So L1L2 = D^8
    but this is the wrong answer and I am confused. Thanks.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Jester's Avatar
    Joined
    Dec 2008
    From
    Conway AR
    Posts
    2,368
    Thanks
    43
    Quote Originally Posted by pberardi View Post
    Can someone help me with this one?
    Find the operator that annihilates this function
    x^4 - x^2 + 11

    I wanna say that the solution is:
    for x^4 L1 = D^5 and for x^2 L2 = D^3
    So L1L2 = D^8
    but this is the wrong answer and I am confused. Thanks.
    There's lots of operators that will annilate this but the easiest is D^5 noting that this operator will annilate everything up to x^4 which includes x^2\;\text{and}\; 11.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Member pberardi's Avatar
    Joined
    Dec 2008
    Posts
    85
    I see but D^5 is the minimum annihilator right? Thanks.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Annihilators of Banach Spaces
    Posted in the Differential Geometry Forum
    Replies: 4
    Last Post: November 29th 2010, 08:38 AM
  2. Annihilators and subspaces
    Posted in the Advanced Algebra Forum
    Replies: 4
    Last Post: March 14th 2010, 03:14 AM
  3. Another question about annihilators
    Posted in the Differential Geometry Forum
    Replies: 0
    Last Post: November 30th 2009, 09:16 AM
  4. null-space and annihilators
    Posted in the Advanced Algebra Forum
    Replies: 2
    Last Post: September 26th 2009, 08:45 AM
  5. Annihilators and torsion R-Modules
    Posted in the Advanced Algebra Forum
    Replies: 1
    Last Post: March 18th 2009, 10:50 PM

Search Tags


/mathhelpforum @mathhelpforum