Thread: help hard math problem

The graph above shows Elina’s height in inches from the age of 6 to 12. Elina’s heighht at the age of 12 was what percent greater than her height at the age of 6?
Age 6: 45 in
Age 8: 50 in
Age 10: 55 in
Age 12: 60 in
The answer is 33.3%, but I don’t know how to do it.. Do I use proportions? HELP!!



Question from Collegeboard's SAT Blue Book, HELP!!!

I did 60/45 then x 100, I got 133.33% Is that correct?

it is (15/45 *100)%

where 15 is the difference in ages,
45 is the age at 6.

Originally Posted by Reefer

The graph above shows Elina’s height in inches from the age of 6 to 12. Elina’s heighht at the age of 12 was what percent greater than her height at the age of 6?
Age 6: 45 in
Age 8: 50 in
Age 10: 55 in
Age 12: 60 in
The answer is 33.3%, but I don’t know how to do it.. Do I use proportions? HELP!!



Question from Collegeboard's SAT Blue Book, HELP!!!

I did 60/45 then x 100, I got 133.33% Is that correct?

Her height at age 12 is 133.33% as tal; as she was age 6, but how much taller was she? 60-45= 15 inches so she is 15 inches taller than at 12: 15/45= 1/3= .33333... so her height is 33.33% greater than at age 6.

You could also say that at age 6 she was already 100% of her height at age 6 so the amount she grew was 133.33- 100= 33.33% of her height then.