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Math Help - help hard math problem

  1. #1
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    The graph above shows Elina’s height in inches from the age of 6 to 12. Elina’s heighht at the age of 12 was what percent greater than her height at the age of 6?
    Age 6: 45 in
    Age 8: 50 in
    Age 10: 55 in
    Age 12: 60 in
    The answer is 33.3%, but I don’t know how to do it.. Do I use proportions? HELP!!



    Question from Collegeboard's SAT Blue Book, HELP!!!

    I did 60/45 then x 100, I got 133.33% Is that correct?
    Last edited by mr fantastic; February 28th 2009 at 09:35 PM. Reason: Merged posts
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  2. #2
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    it is (15/45 *100)%

    where 15 is the difference in ages,
    45 is the age at 6.
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  3. #3
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    Quote Originally Posted by Reefer View Post
    The graph above shows Elina’s height in inches from the age of 6 to 12. Elina’s heighht at the age of 12 was what percent greater than her height at the age of 6?
    Age 6: 45 in
    Age 8: 50 in
    Age 10: 55 in
    Age 12: 60 in
    The answer is 33.3%, but I don’t know how to do it.. Do I use proportions? HELP!!



    Question from Collegeboard's SAT Blue Book, HELP!!!

    I did 60/45 then x 100, I got 133.33% Is that correct?
    Her height at age 12 is 133.33% as tal; as she was age 6, but how much taller was she? 60-45= 15 inches so she is 15 inches taller than at 12: 15/45= 1/3= .33333... so her height is 33.33% greater than at age 6.

    You could also say that at age 6 she was already 100% of her height at age 6 so the amount she grew was 133.33- 100= 33.33% of her height then.
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