Hello,

This is tricky, or I didn't get the thing

Let x be the length of the wire bent to a circle and y to form a square.

**Let's study the circle**
x is its perimeter, which is also

, where R is the radius. According to it, we have the equation

The area enclosed by the circle is

, which is also

**Let's study the square** is its perimeter.

If q is the length of the side of the square, the perimeter is 4q.

Hence

The area of a square is

.

**Total area**
So find the derivative and see, in the interval [0,

75] (since the wire is

75 cm long) where the maximum is and where the minimum is