min. Areas, Given Length of Wire for perimeter

A friend and I have tried this question waaaay too long. It's calculus and we cannot solve this dumb question to get the right answer !

Question: A piece of wire 75m long is divided into two pieces. One piece is used to form a circle. The other piece is used to make a square. Find the lengths of the pieces that maximize the total area.

Our work: We have two pieces --> length y and (75-y)

Psquare = (75-y)

side of the square is (75-y)/4

Circum. circle = 2pi(r) , y/2pi=r

Asquare = side^2

Acircle=(y^2)/4

You see I did quite a bit of work... basically, I subbed in to minimize the following eq'n:

pi(r)^2+s^2

= (y^2)/4 + ((75-y)^2) /16

and I keep getting weird numbers.

Pleeease, someone tell me what is wrong here because we have checked over and over for hours!