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Math Help - Tricky Integral

  1. #1
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    Tricky Integral

    I am having problems with the following integral:

    (1/sqrt(2pi))*e^((-x^2)/2)dx, from x=0 to x=1. I know I can bring the
    1/sqrt(2pi) outside the integral since it is just a constant, but I'm not sure how to integrate the e part of the expression. Any ideas or help would be great. Thanks.
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  2. #2
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    try using elliptic integrals.u can find the value to any desired degree of accuracy by expanding their integrands as power series.
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  3. #3
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    Wow, I pretty much have no idea of what you are talking about. I've never taken elliptical integrals in any of the calculus classes I've taken. Is there a simpler method available, or can someone explain how to do this question using elliptic integrals?
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  4. #4
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    no,there is no other simple way available.

    this is the only possible way.

    u just expand it in the e-series which is an infinite series & then look for your desired level of accuracy.
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  5. #5
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    Quote Originally Posted by eigenvector11 View Post
    I am having problems with the following integral:

    (1/sqrt(2pi))*e^((-x^2)/2)dx, from x=0 to x=1. I know I can bring the
    1/sqrt(2pi) outside the integral since it is just a constant, but I'm not sure how to integrate the e part of the expression. Any ideas or help would be great. Thanks.
    Quote Originally Posted by sbcd90 View Post
    try using elliptic integrals.u can find the value to any desired degree of accuracy by expanding their integrands as power series.
    Actually it's the Error function Erf(x) that's required here if an 'exact answer' is wanted.

    Quote Originally Posted by eigenvector11 View Post
    I am having problems with the following integral:

    (1/sqrt(2pi))*e^((-x^2)/2)dx, from x=0 to x=1. I know I can bring the
    1/sqrt(2pi) outside the integral since it is just a constant, but I'm not sure how to integrate the e part of the expression. Any ideas or help would be great. Thanks.
    Why do you want to find this integral? Where has it come from? What makes you think an exact answer is required?
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