if y=f(√(x²+9) and f'(5)=-2, find dy/dx when x=4
Last edited by hawtmonkey; February 26th 2009 at 10:41 PM.
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Originally Posted by hawtmonkey if y=f(√(x²+9) and f'(5)=-2, find dy/dx when x=4 Look at it like , where g(x) is the square root. Now just use the normal chain rule to find . Notice that g(4)=5 so that's why that extra bit was given to you. So now all you have to do is find g'[5].
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