Thread: Integration - Im stumped

I should know this but I cannot figure it out.

The problem is.

integrate Cot[x]/Sqrt[Sin[x]] dx

I convert the Cot[x] into Cos[x]/Sin[x]

I assume this problem is done by u-substitution. I cant figure out what to set u = ?

Thanks for you help.

Just set your U substitution with u=sin(x) and that will get you to the end, good luck.

you can do it without u substitution (unless it is required). Just make the bottom sinx^(3/2) and you should be able to do it no problem ... I personally dont like u substitution too much, too much work.

I have tried that but I get lost.

So here is where I am at.

Integral (Cos[x]/Sin[x])/Sqrt[Sin[x]] dx

Let u = sinx
du = cosx

I am not sure how the problem will look after the substitution.

I think I got it.

(-2)/Sqrt[Sin[x]] + C


I liked that idea of just combining the Sin's into sin^(3/2).


Thanks for the help everyone!

yeah thats what I got

Originally Posted by aervid

you can do it without u substitution (unless it is required). Just make the bottom sinx^(3/2) and you should be able to do it no problem ... I personally dont like u substitution too much, too much work.

Personally I'd advise that a beginner should always attempt this sort of integral making the substitution suggested earlier.