ok so say you have
the lim as x approaches -1 from the right f(x) = f(-3)
Apparently it's true by looking at the graph. The point at f(-3) =1.
And as lim as x approaches -1 from the right, it is an open circle which is 1 and a closed circle which is 2.
-I don't know why that is true since f(x) = 2 points where one is and open point and one is a closed point...I thought if you had an open and closed point then that would mean it isn't continuous or differentiable or something?