find the volume of the solid whose base is the area bounded by the lines y=1-(x/2), y=(x/2)-1 and x=0 and whose cross sections perpendicular to the x axis are equilateral triangles.
do i do v=the integral of (1/2)(2x*x) dx
that seems too simple...
also, find the volume of the solid generated by revolving the region bounded by the graph y=x^2, y=4x-x^2 and revolved about the line y=6
i got 64/3 pi, is this right?
what am i doing wrong in these two problems?