integral(x/(x^2+4x+13),x,0,1) I broke the bottom up to (x+2)^2 + 9, but now I"m stuck. any help would be very appreciated. Thanks, s3n4te edit: i think i should now use inverse trig substitution.
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Hi 2x+4)}{x^2+4x+13} - \frac{2}{(x+2)^2+9}" alt="\frac{x}{x^2+4x+13} = \frac{\frac{1}{2}\2x+4)}{x^2+4x+13} - \frac{2}{(x+2)^2+9}" /> The first part is integrable in The second part is integrable in Arctan after setting x+2=3t
How do you know how to split that up like that?
Originally Posted by s3n4te How do you know how to split that up like that? By experience You make appear eventually using a multiplicative constant - here The other part is then integrable with Arctan (this is true because the denominator has no real roots)
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