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Math Help - Calculus...graphs/derivatives

  1. #1
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    Calculus...graphs/derivatives

    http://i42.tinypic.com/scv191.jpg

    The problem, answer, and my questions are all in there ^^

    Thanks in advance for any insight!
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  2. #2
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    Hello, janedoe!

    Looks good! . . . Nice work!

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  3. #3
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    I think you misunderstood me...that's the book's answer, but I don't know how they got it. My questions are in blue at the bottom.
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  4. #4
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    Uh, Soroban, that picture is copied from the answer key and is what janedoe is asking about!

    janedoe, exactly how you would put it into a calculator depends on the calculator.

    You certainly should be able to put in y1= (2(x+ 0.01)- (x+0.01)^2- 2(x)+ x^2)/0.01, for the straight line. The parabola is, of course, [tex]y2= 2x- x^2[/itex].

    Finally, they know it is "similar to graph of the derivative of f(x)" because the derivative is given by \lim_{h\rightarrow 0}\frac{f(x+h)- f(x)}{h} and 0.01 is not very far from 0.
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