Using the fact that $x \rightarrow logx$ is differentiable on $(0,\infty)$ with derivative $x \rightarrow \frac {1} {x}$ verify that $arctanh x=\frac {1} {2} log ( \frac {1+x} {1-x})$ is differentiable and compute its derivative. Now I have no problem finding the derivative, however I'm not sure how to show it is differentiable. It shouldn't be too hard but I'm not too acquainted with the method. Thanks!!
Using the fact that $x \rightarrow logx$ is differentiable on $(0,\infty)$ with derivative $x \rightarrow \frac {1} {x}$ verify that $arctanh x=\frac {1} {2} log ( \frac {1+x} {1-x})$ is differentiable and compute its derivative. Now I have no problem finding the derivative, however I'm not sure how to show it is differentiable. It shouldn't be too hard but I'm not too acquainted with the method. Thanks!!
Hi, I think you must specify that it's differentiable somewhere. Indeed it's only well defined for $x\in]-1,1[$, so you can use the result on the composition of differentiable functions in that interval.