It's the indefinite integral of (3x-7)^1.7 dx I don't even know where I'd begin finding that antiderivative, maybe substitution of some sort? Could someone walk me through this?
$\displaystyle \int{(3x - 7)^{1.7}\,dx} = \frac{1}{3}\int{(3x - 7)^{1.7}\cdot 3\,dx}$
Let $\displaystyle u = 3x - 7$ so that $\displaystyle \frac{du}{dx} = 3$.
So the integral becomes
$\displaystyle \frac{1}{3}\int{u^{1.7}\frac{du}{dx}\,dx} = \frac{1}{3}\int{u^{1.7}\,du}$.
I trust you can go from here