It's the indefinite integral of (3x-7)^1.7 dx I don't even know where I'd begin finding that antiderivative, maybe substitution of some sort? Could someone walk me through this?
It's the indefinite integral of (3x-7)^1.7 dx I don't even know where I'd begin finding that antiderivative, maybe substitution of some sort? Could someone walk me through this?
Let and use the power rule. This one is pretty easy.
It's the indefinite integral of (3x-7)^1.7 dx I don't even know where I'd begin finding that antiderivative, maybe substitution of some sort? Could someone walk me through this?
Let and use the power rule. This one is pretty easy.
So it would end up being 1/3 the integral of u^1.7 which would end up being (u^2.7)/2.7 times 1/3, with u resub'd back in? so 1/3 times (3x-7)^2.7 over 2.7?
Originally Posted by Prove It
Let so that .
So the integral becomes
.
I trust you can go from here
So my final answer would just be 1/3 times (3x-7)^2.7/2.7?
Last edited by mr fantastic; Feb 26th 2009 at 02:52 AM.
Reason: Merged posts