find the volume of the area enclosed by Y=X^2+1, Y=0, X=2 and revolved around X=3
Using the Disk Method
I used the shell method and got: 175pi/3
But I need to know how to set up the disk integral
Also,
Y=X^2+1, X=0, Y=5 revolved around Y=7
using the shell method i think i got 12pi, but that may be wrong, and I need to know how to set up the disk method.
thanks so much
1. If I understand your question correctly the solid looks like a kind of funnel (upside down). (See attachment)
2. The solid consists of two different kinds of solids:
The base is a cylindrical ring with height of 1.
The top is the funnel mentioned above.
3. The base area of one disk is
the height of one disk is
From
4. The complete volume is:
I leave the rest for you.
By the way: Your result must be too large: The solid can be placed completely into a cylinder with a base diameter of 6 and a height of 5. Such a cylinder has a volume of