you are given , and the problem wants you to find when the surface area =
since surface area =
finish up
The radius r of a sphere is increasing at the uniform rate of .3 inches per second. At the instant when the surface area S becomes 100pi square inches, what if the rate of increase, in cubic inches per second, in the volume V?
s=4pir^2 v=(4/3)pir^2
:/ All I know is a have to take the derivative of each. ><"